




'''simple docstring'''

from __future__ import annotations




def    snake_case__     (  a	)			->       list[int]:





			'''simple docstring'''






			snake_case__          =						[0] * max_one

			for i in range(0       ,      a	):
						snake_case__          =						i

			for i in range(2       ,      a	):
						if totients[i] == i:
									for j in range(a       ,      a       ,      a	):
												totients[j] -= totients[j] // i

			return totients




def    snake_case__     (  a       ,      a	)			->       bool:





			'''simple docstring'''






			return sorted(str(a	)	) == sorted(str(a	)	)




def    snake_case__     (  a = 1000_0000	)			->       int:





			'''simple docstring'''






			snake_case__          =						1  # i
			snake_case__          =						0  # φ(i)
			snake_case__          =						get_totients(max_n + 1	)

			for i in range(2       ,      max_n + 1	):
						snake_case__          =						totients[i]

						if i * min_denominator < min_numerator * t and has_same_digits(a       ,      a	):
									snake_case__          =						i
									snake_case__          =						t

			return min_numerator


if __name__ == "__main__":
		print(F"{solution() = }")







"""simple docstring"""



from string import ascii_uppercase




def       snake_case__		(   _SCREAMING_SNAKE_CASE       ,	_SCREAMING_SNAKE_CASE       ,	_SCREAMING_SNAKE_CASE = False       ,	_SCREAMING_SNAKE_CASE = ascii_uppercase			)    ->str:
 UpperCAmelCase__ 						=				keyword.upper()
 UpperCAmelCase__ 						=				plaintext.upper()
 UpperCAmelCase__ 						=				set(_SCREAMING_SNAKE_CASE			)

 # create a list of unique characters in the keyword - their order matters
 # it determines how we will map plaintext characters to the ciphertext
 UpperCAmelCase__ 						=				[]
 for char in keyword:
  if char in alphabet_set and char not in unique_chars:
   unique_chars.append(_SCREAMING_SNAKE_CASE			)
    # the number of those unique characters will determine the number of rows
 UpperCAmelCase__ 						=				len(_SCREAMING_SNAKE_CASE			)

 # create a shifted version of the alphabet
 UpperCAmelCase__ 						=				unique_chars + [
     char for char in alphabet if char not in unique_chars
 ]

 # create a modified alphabet by splitting the shifted alphabet into rows
 UpperCAmelCase__ 						=				[
     shifted_alphabet[k : k + num_unique_chars_in_keyword]
     for k in range(0       ,	2_6       ,	_SCREAMING_SNAKE_CASE			)
 ]

 # map the alphabet characters to the modified alphabet characters
 # going 'vertically' through the modified alphabet - consider columns first
 UpperCAmelCase__ 						=				{}
 UpperCAmelCase__ 						=				0
 for column in range(_SCREAMING_SNAKE_CASE			):
  for row in modified_alphabet:
   # if current row (the last one) is too short, break out of loop
   if len(_SCREAMING_SNAKE_CASE			) <= column:
    break

   # map current letter to letter in modified alphabet
   UpperCAmelCase__ 						=				row[column]
   letter_index += 1

 if verbose:
  print(_SCREAMING_SNAKE_CASE			)
 # create the encrypted text by mapping the plaintext to the modified alphabet
 return "".join(mapping[char] if char in mapping else char for char in plaintext			)


if __name__ == "__main__":
 # example use
 print(mixed_keyword('''college''', '''UNIVERSITY'''))



