



'''simple docstring'''






from __future__ import annotations




def 					snake_case_      (  lowerCAmelCase_	)->	Tuple:





       '''simple docstring'''


       if len(lowercase_	) == 0:
              raise ValueError("""find_min() arg is an empty sequence"""	)
       _UpperCAmelCase						:		str      =				nums[0]
       for num in nums:
              _UpperCAmelCase						:		List[Any]      =				min(lowercase_ ,     lowercase_	)
       return min_num


if __name__ == "__main__":
   import doctest

   doctest.testmod(verbose=True)








'''simple docstring'''






from string import ascii_uppercase




def 					snake_case_      (  lowerCAmelCase_ ,     lowerCAmelCase_ ,     lowerCAmelCase_ = False ,     lowerCAmelCase_ = ascii_uppercase	)->	str:





       '''simple docstring'''


       _UpperCAmelCase						:		List[str]      =				keyword.upper()
       _UpperCAmelCase						:		Optional[int]      =				plaintext.upper()
       _UpperCAmelCase						:		Optional[int]      =				set(lowerCAmelCase_	)

       # create a list of unique characters in the keyword - their order matters
       # it determines how we will map plaintext characters to the ciphertext
       _UpperCAmelCase						:		str      =				[]
       for char in keyword:
              if char in alphabet_set and char not in unique_chars:
                     unique_chars.append(lowerCAmelCase_	)
    # the number of those unique characters will determine the number of rows
       _UpperCAmelCase						:		Optional[Any]      =				len(lowerCAmelCase_	)

       # create a shifted version of the alphabet
       _UpperCAmelCase						:		Optional[Any]      =				unique_chars + [
           char for char in alphabet if char not in unique_chars
       ]

       # create a modified alphabet by splitting the shifted alphabet into rows
       _UpperCAmelCase						:		List[str]      =				[
           shifted_alphabet[k : k + num_unique_chars_in_keyword]
           for k in range(0 ,     26 ,     lowerCAmelCase_	)
       ]

       # map the alphabet characters to the modified alphabet characters
       # going 'vertically' through the modified alphabet - consider columns first
       _UpperCAmelCase						:		int      =				{}
       _UpperCAmelCase						:		int      =				0
       for column in range(lowerCAmelCase_	):
              for row in modified_alphabet:
                     # if current row (the last one) is too short, break out of loop
                     if len(lowerCAmelCase_	) <= column:
                            break

                     # map current letter to letter in modified alphabet
                     _UpperCAmelCase						:		Optional[int]      =				row[column]
                     letter_index += 1

       if verbose:
              print(lowerCAmelCase_	)
       # create the encrypted text by mapping the plaintext to the modified alphabet
       return "".join(mapping[char] if char in mapping else char for char in plaintext	)


if __name__ == "__main__":
   # example use
   print(mixed_keyword("""college""", """UNIVERSITY"""))



