from string import ascii_uppercase





def      __lowercase  (		lowerCamelCase      :  str						,						lowerCamelCase      :  str						,						lowerCamelCase      :  bool = False						,						lowerCamelCase      :  str = ascii_uppercase			):
 UpperCamelCase_      :		List[Any]				=      keyword.upper()
 UpperCamelCase_      :		int				=      plaintext.upper()
 UpperCamelCase_      :		int				=      set(lowerCamelCase			)

 # create a list of unique characters in the keyword - their order matters
 # it determines how we will map plaintext characters to the ciphertext
 UpperCamelCase_      :		Optional[int]				=      []
 for char in keyword:
  if char in alphabet_set and char not in unique_chars:
   unique_chars.append(lowerCamelCase			)
    # the number of those unique characters will determine the number of rows
 UpperCamelCase_      :		int				=      len(lowerCamelCase			)

 # create a shifted version of the alphabet
 UpperCamelCase_      :		int				=      unique_chars + [
     char for char in alphabet if char not in unique_chars
 ]

 # create a modified alphabet by splitting the shifted alphabet into rows
 UpperCamelCase_      :		Union[str, Any]				=      [
     shifted_alphabet[k : k + num_unique_chars_in_keyword]
     for k in range(0						,						26						,						lowerCamelCase			)
 ]

 # map the alphabet characters to the modified alphabet characters
 # going 'vertically' through the modified alphabet - consider columns first
 UpperCamelCase_      :		Dict				=      {}
 UpperCamelCase_      :		str				=      0
 for column in range(lowerCamelCase			):
  for row in modified_alphabet:
   # if current row (the last one) is too short, break out of loop
   if len(lowerCamelCase			) <= column:
    break

   # map current letter to letter in modified alphabet
   UpperCamelCase_      :		Tuple				=      row[column]
   letter_index += 1

 if verbose:
  print(lowerCamelCase			)
 # create the encrypted text by mapping the plaintext to the modified alphabet
 return "".join(mapping[char] if char in mapping else char for char in plaintext			)


if __name__ == "__main__":
   # example use
   print(mixed_keyword('college', 'UNIVERSITY'))




def      __lowercase  (		lowerCamelCase      :  int = 998001			):
 UpperCamelCase_      :		int				=      0
 for i in range(999						,						99						,						-1			):  # 3 digit numbers range from 999 down to 100
  for j in range(999						,						99						,						-1			):
   UpperCamelCase_      :		str				=      str(i * j			)
   if product_string == product_string[::-1] and i * j < n:
    UpperCamelCase_      :		str				=      max(lowerCamelCase						,						i * j			)
 return answer


if __name__ == "__main__":
   print(F"""{solution() = }""")



