



'''simple docstring'''






def 					snake_case_      (  lowerCAmelCase_	)->	list:





       '''simple docstring'''


       _UpperCAmelCase						:		Any      =				[]
       _UpperCAmelCase						:		Union[str, Any]      =				1

       for i in range(len(_UpperCAmelCase	)	):
              if i + 1 < len(_UpperCAmelCase	) and text[i] == text[i + 1]:
                     count += 1
              else:
                     encoded.append((text[i], count)	)
                     _UpperCAmelCase						:		Optional[int]      =				1

       return encoded




def 					snake_case_      (  lowerCAmelCase_	)->	str:





       '''simple docstring'''


       return "".join(char * length for char, length in encoded	)


if __name__ == "__main__":
   from doctest import testmod

   testmod(name="""run_length_encode""", verbose=True)
   testmod(name="""run_length_decode""", verbose=True)








'''simple docstring'''






from string import ascii_uppercase




def 					snake_case_      (  lowerCAmelCase_ ,     lowerCAmelCase_ ,     lowerCAmelCase_ = False ,     lowerCAmelCase_ = ascii_uppercase	)->	str:





       '''simple docstring'''


       _UpperCAmelCase						:		List[str]      =				keyword.upper()
       _UpperCAmelCase						:		Optional[int]      =				plaintext.upper()
       _UpperCAmelCase						:		Optional[int]      =				set(lowerCAmelCase_	)

       # create a list of unique characters in the keyword - their order matters
       # it determines how we will map plaintext characters to the ciphertext
       _UpperCAmelCase						:		str      =				[]
       for char in keyword:
              if char in alphabet_set and char not in unique_chars:
                     unique_chars.append(lowerCAmelCase_	)
    # the number of those unique characters will determine the number of rows
       _UpperCAmelCase						:		Optional[Any]      =				len(lowerCAmelCase_	)

       # create a shifted version of the alphabet
       _UpperCAmelCase						:		Optional[Any]      =				unique_chars + [
           char for char in alphabet if char not in unique_chars
       ]

       # create a modified alphabet by splitting the shifted alphabet into rows
       _UpperCAmelCase						:		List[str]      =				[
           shifted_alphabet[k : k + num_unique_chars_in_keyword]
           for k in range(0 ,     26 ,     lowerCAmelCase_	)
       ]

       # map the alphabet characters to the modified alphabet characters
       # going 'vertically' through the modified alphabet - consider columns first
       _UpperCAmelCase						:		int      =				{}
       _UpperCAmelCase						:		int      =				0
       for column in range(lowerCAmelCase_	):
              for row in modified_alphabet:
                     # if current row (the last one) is too short, break out of loop
                     if len(lowerCAmelCase_	) <= column:
                            break

                     # map current letter to letter in modified alphabet
                     _UpperCAmelCase						:		Optional[int]      =				row[column]
                     letter_index += 1

       if verbose:
              print(lowerCAmelCase_	)
       # create the encrypted text by mapping the plaintext to the modified alphabet
       return "".join(mapping[char] if char in mapping else char for char in plaintext	)


if __name__ == "__main__":
   # example use
   print(mixed_keyword("""college""", """UNIVERSITY"""))



