

from __future__ import annotations


class     lowerCAmelCase				:


       '''simple docstring'''







       def __init__(	self					:  Dict						,	__snake_case					:  int     )   -> None:







        '''simple docstring'''

        lowerCamelCase      						=    vertices
        lowerCamelCase      						=    [[0] * vertices for _ in range(__snake_case     )]

       def   lowerCamelCase__						(	self					:  List[str]						,	__snake_case					:  list[int]     )   -> None:







        '''simple docstring'''

        print('Vertex \t Distance from Source'     )
        for vertex in range(self.vertices     ):
         print(__snake_case						,	'\t\t'						,	distances_from_source[vertex]     )

       def   lowerCamelCase__						(	self					:  Optional[int]						,	__snake_case					:  list[int]						,	__snake_case					:  list[bool]     )   -> int:







        '''simple docstring'''

        lowerCamelCase      						=    1e7
        lowerCamelCase      						=    0

        # Search not nearest vertex not in the shortest path tree
        for vertex in range(self.vertices     ):
         if distances_from_source[vertex] < minimum and visited[vertex] is False:
          lowerCamelCase      						=    distances_from_source[vertex]
          lowerCamelCase      						=    vertex
        return min_index





       def   lowerCamelCase__						(	self					:  Optional[Any]						,	__snake_case					:  int     )   -> None:







        '''simple docstring'''

        lowerCamelCase      						=    [int(1e7     )] * self.vertices  # distances from the source
        lowerCamelCase      						=    0
        lowerCamelCase      						=    [False] * self.vertices

        for _ in range(self.vertices     ):
         lowerCamelCase      						=    self.minimum_distance(__snake_case						,	__snake_case     )
         lowerCamelCase      						=    True

         # Update dist value of the adjacent vertices
         # of the picked vertex only if the current
         # distance is greater than new distance and
         # the vertex in not in the shortest path tree
         for v in range(self.vertices     ):
          if (
              self.graph[u][v] > 0
              and visited[v] is False
              and distances[v] > distances[u] + self.graph[u][v]
          ):
           lowerCamelCase      						=    distances[u] + self.graph[u][v]

        self.print_solution(__snake_case     )


if __name__ == "__main__":
     _lowerCAmelCase :	Dict     				=    Graph(9)
     _lowerCAmelCase :	int     				=    [
         [0, 4, 0, 0, 0, 0, 0, 8, 0],
         [4, 0, 8, 0, 0, 0, 0, 1_1, 0],
         [0, 8, 0, 7, 0, 4, 0, 0, 2],
         [0, 0, 7, 0, 9, 1_4, 0, 0, 0],
         [0, 0, 0, 9, 0, 1_0, 0, 0, 0],
         [0, 0, 4, 1_4, 1_0, 0, 2, 0, 0],
         [0, 0, 0, 0, 0, 2, 0, 1, 6],
         [8, 1_1, 0, 0, 0, 0, 1, 0, 7],
         [0, 0, 2, 0, 0, 0, 6, 7, 0],
     ]
     graph.dijkstra(0)







def a_		(       UpperCamelCase_   :							int   ,					UpperCamelCase_   :							list  )							->   list:







 """simple docstring"""

 lowerCamelCase      						=    sorted(UpperCamelCase_   ,					key=lambda UpperCamelCase_  : value[2]   ,					reverse=UpperCamelCase_  )

 # Create a list of size equal to the maximum deadline
 # and initialize it with -1
 lowerCamelCase      						=    max(UpperCamelCase_   ,					key=lambda UpperCamelCase_  : value[1]  )[1]
 lowerCamelCase      						=    [-1] * max_deadline

 # Finding the maximum profit and the count of jobs
 lowerCamelCase      						=    0
 lowerCamelCase      						=    0
 for job in jobs:
  # Find a free time slot for this job
  # (Note that we start from the last possible slot)
  for i in range(job[1] - 1   ,					-1   ,					-1  ):
   if time_slots[i] == -1:
    lowerCamelCase      						=    job[0]
    count += 1
    max_profit += job[2]
    break
 return [count, max_profit]


if __name__ == "__main__":
     import doctest

     doctest.testmod()




