



from __future__ import annotations

def       A_   (						__a  :					int			,		__a  :					list[int]			,		__a  :					list[int]			,		__a  :					int		):

				"""simple docstring"""

				# Base Case
				if counter == 0 or capacity == 0:
								return 0

				# If weight of the nth item is more than Knapsack of capacity,
				#   then this item cannot be included in the optimal solution,
				# else return the maximum of two cases:
				#   (1) nth item included
				#   (2) not included
				if weights[counter - 1] > capacity:
								return knapsack(__a			,		__a			,		__a			,		counter - 1		)
				else:
								a__					   =		capacity - weights[counter - 1]
								a__					   =		values[counter - 1] + knapsack(
								    __a			,		__a			,		__a			,		counter - 1		)
								a__					   =		knapsack(__a			,		__a			,		__a			,		counter - 1		)
								return max(__a			,		__a		)


if __name__ == "__main__":
	import doctest

	doctest.testmod()





def 			__lowerCAmelCase       (SCREAMING_SNAKE_CASE = 1000   )->    int:




      """simple docstring"""

      snake_case_			= [0, 3, 3, 5, 4, 4, 3, 5, 5, 4, 3, 6, 6, 8, 8, 7, 7, 9, 8, 8]
      # number of letters in twenty, thirty, ..., ninety (0 for numbers less than
      # 20 due to inconsistency in teens)
      snake_case_			= [0, 0, 6, 6, 5, 5, 5, 7, 6, 6]

      snake_case_			= 0

      for i in range(1   ,   n + 1   ):
            if i < 1000:
                  if i >= 100:
                        # add number of letters for "n hundred"
                        count += ones_counts[i // 100] + 7

                        if i % 100 != 0:
                              # add number of letters for "and" if number is not multiple
                              # of 100
                              count += 3

                  if 0 < i % 100 < 20:
                        # add number of letters for one, two, three, ..., nineteen
                        # (could be combined with below if not for inconsistency in
                        # teens)
                        count += ones_counts[i % 100]
                  else:
                        # add number of letters for twenty, twenty one, ..., ninety
                        # nine
                        count += ones_counts[i % 10]
                        count += tens_counts[(i % 100 - i % 10) // 10]
            else:
                  count += ones_counts[i // 1000] + 8
      return count


if __name__ == "__main__":
   print(solution(int(input().strip())))