

from functools import lru_cache







@lru_cache
def a_		(       UpperCamelCase_   :							int  )							->   int:







 """simple docstring"""

 if not isinstance(UpperCamelCase_   ,					UpperCamelCase_  ):
  raise TypeError('k must be an integer.'  )
 if k < 0:
  raise ValueError('k integer must be greater or equal to zero.'  )
 if k == 0:
  return 0
 elif k == 1:
  return 1
 else:
  return fibonacci(k - 1  ) + fibonacci(k - 2  )







def a_		(       UpperCamelCase_   :							list   ,					UpperCamelCase_   :							int  )							->   int:







 """simple docstring"""

 lowerCamelCase      						=    len(UpperCamelCase_  )
 # Find m such that F_m >= n where F_i is the i_th fibonacci number.
 lowerCamelCase      						=    0
 while True:
  if fibonacci(UpperCamelCase_  ) >= len_list:
   lowerCamelCase      						=    i
   break
  i += 1
 lowerCamelCase      						=    0
 while fibb_k > 0:
  lowerCamelCase      						=    min(
      offset + fibonacci(fibb_k - 1  )   ,					len_list - 1  )  # Prevent out of range
  lowerCamelCase      						=    arr[index_k]
  if item_k_1 == val:
   return index_k
  elif val < item_k_1:
   fibb_k -= 1
  elif val > item_k_1:
   offset += fibonacci(fibb_k - 1  )
   fibb_k -= 2
 else:
  return -1


if __name__ == "__main__":
     import doctest

     doctest.testmod()









def a_		(       UpperCamelCase_   :							int   ,					UpperCamelCase_   :							list  )							->   list:







 """simple docstring"""

 lowerCamelCase      						=    sorted(UpperCamelCase_   ,					key=lambda UpperCamelCase_  : value[2]   ,					reverse=UpperCamelCase_  )

 # Create a list of size equal to the maximum deadline
 # and initialize it with -1
 lowerCamelCase      						=    max(UpperCamelCase_   ,					key=lambda UpperCamelCase_  : value[1]  )[1]
 lowerCamelCase      						=    [-1] * max_deadline

 # Finding the maximum profit and the count of jobs
 lowerCamelCase      						=    0
 lowerCamelCase      						=    0
 for job in jobs:
  # Find a free time slot for this job
  # (Note that we start from the last possible slot)
  for i in range(job[1] - 1   ,					-1   ,					-1  ):
   if time_slots[i] == -1:
    lowerCamelCase      						=    job[0]
    count += 1
    max_profit += job[2]
    break
 return [count, max_profit]


if __name__ == "__main__":
     import doctest

     doctest.testmod()




